teamomiamor replied to your post: so you are never coming back?
You should just be in the ‘whoever the hell you want’ fandom :p Glee will be over with soon, no doubt.
Hahahaha, I really should. :P I heard they aren’t signed for Season 5 yet, and with Cory being in rehab and Heather being pregnant, the show will really be going to ruin. I think it’s time they all said goodbye and moved on to bigger and better things.
Anonymous said: so you are never coming back?
I really don’t know. :/ At the moment I’m having the dilemma of really wanting to be in the Naya fandom but without being in the Glee fandom, but that’s hardly possible. :/
Anonymous said: where are you :(
I’ve been staying on my Lord of the Rings Tumblr. I still haven’t been on my dashboard since they announced Quinntana were going to sleep with each other. :/ It hurts too much to think about it, let alone see it. I’m sorry. :(
Anonymous said: Could you please vote for Brittana on the e!poll and tell your followers to do too? We really need to win!! Thanks :)
Anonymous said: Thank you so much!!! I really appreciate it :D
You’re welcome! Anytime. :)
Anonymous said: Did you think you could possibly help me? I'm trying to differentiate y = x ln^3 x but I have no clue how to do it.
Sure! :) So you’re gonna have to use the product rule for this one, which is (f * g)’ = (f ‘ * g) + (f * g’ ). In this case, your f is x, and your g is ln^3(x). So if we take the first part of the product rule, we want to multiply the derivative of f, which is 1, times g, so you have (1)(ln^3(x)) = ln^3(x). For the second part, you want to multiply f by the derivative of g, and to get the derivative of g, you need to use the chain rule. The chain rule is basically you just differentiate the outermost action first, keeping what’s inside as it is, then differentiate the second part, and so forth. So in this case, the first thing we have to do with ln^3(x) is take the derivative of the power, so you’ll get 3ln^2(x). Now you have to take the derivative of what’s inside, which is ln(x), and the derivative of that is 1/x. So putting it all together, g’ is 3ln^2(x)*(1/x). Now you just plug all of this in to the product rule equation, so you have (f ‘ * g) + (f * g’ ) = (1)(ln^3(x))+(x)((3ln^2(x))(1/x)), and the x’s cancel out in the second half, so you have ln^3(x) + 3ln^2(x), and that’s your answer. :)